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H5PS5182GFRS6I 数据表(PDF) 43 Page - Hynix Semiconductor |
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H5PS5182GFRS6I 数据表(HTML) 43 Page - Hynix Semiconductor |
43 / 64 page Rev.1.7 / Feb. 2013 43 H5PS5162GFR series to 0.5. For example, if an input clock has a worst case tCH (avg) of 0.48, the tAOF, min should be derated by subtracting 0.02 x tCK (avg) from it, whereas if an input clock has a worst case tCH (avg) of 0.52, the tAOF, max should be derated by adding 0.02 x tCK (avg) to it. Therefore, we have; tAOF, min (derated) = tAC, min - [0.5 - Min(0.5, tCH (avg), min)] x tCK (avg) tAOF, max (derated) = tAC, max + 0.6 + [Max(0.5, tCH (avg), max) - 0.5] x tCK (avg) or tAOF, min (derated) = Min (tAC, min, tAC, min - [0.5 - tCH (avg), min] x tCK (avg)) tAOF, max (derated) = 0.6 + Max (tAC, max, tAC, max + [tCH (avg), max - 0.5] x tCK (avg)) where tCH (avg), min and tCH (avg), max are the minimum and maximum of tCH (avg) actually measured at the DRAM input balls. Note that these deratings are in addition to the tAOF derating per input clock jitter, i.e. tJIT (duty) and tERR(6-10per). However tAC values used in the equations shown above are from the timing parameter table and are not derated. Thus the final derated values for tAOF are; tAOF, min (derated _ final) = tAOF, min (derated) + {- tJIT (duty), max - tERR(6-10per),max} tAOF, max (derated _ final) = tAOF, max (derated) + {- tJIT (duty), min - tERR(6-10per),min} |
类似零件编号 - H5PS5182GFRS6I |
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类似说明 - H5PS5182GFRS6I |
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