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AD8565AKSZ-REEL7 数据表(PDF) 11 Page - Analog Devices |
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AD8565AKSZ-REEL7 数据表(HTML) 11 Page - Analog Devices |
11 / 16 page AD8565/AD8566/AD8567 Rev. D | Page 11 of 16 TOTAL HARMONIC DISTORTION + NOISE (THD+N) LCD PANEL APPLICATIONS The AD856x amplifier is designed for LCD panel applications or applications where large capacitive load drive is required. It can instantaneously source/sink greater than 250 mA of current. At unity gain, it can drive 1 μF without compensation. This makes the AD856x ideal for LCD VCOM driver applications. The AD856x family features low total harmonic distortion. Figure 31 shows THD+N vs. frequency. The THD+N for the AD856x over the entire supply range is below 0.008%. When the device is powered from a 16 V supply, the THD+N stays below 0.003%. Figure 31 shows the AD8566 in a unity noninverting configuration. To evaluate the performance of the AD856x family, a test circuit was developed to simulate the VCOM driver application for an LCD panel. FREQUENCY (Hz) 20 100 10 1 0.01 0.1 1k 10k 30k VS = ±2.5V VS = ±8V Figure 32 shows the test circuit. Series capacitors and resistors connected to the output of the op amp represent the load of the LCD panel. The 300 Ω and 3 kΩ feedback resistors are used to improve settling time. This test circuit simulates the worst-case scenario for a VCOM. It drives a represented load that is connected to a signal switched symmetrically around VCOM. Figure 33 shows a scope photo of the instantaneous output peak current capability of the AD856x family. INPUT 0VTO 8V SQUARE WAVE WITH 15.6µs PULSE WIDTH 300Ω 3kΩ 10Ω 10Ω 10Ω 10Ω 10nF 10nF 10nF 10nF MEASURE CURRENT 4V 8V 10Ω TO 20Ω Figure 31. THD+N vs. Frequency SHORT-CIRCUIT OUTPUT CONDITIONS The AD856x family does not have internal short-circuit protection circuitry. As a precautionary measure, it is recommended not to short the output directly to the positive power supply or to ground. Figure 32. VCOM Test Circuit with Supply Voltage at 16 V It is not recommended to operate the AD856x with more than 35 mA of continuous output current. The output current can be limited by placing a series resistor at the output of the amplifier whose value can be derived using TIME (2µs/DIV) CH 2 = 100mA/DIV CH 1 = 5V/DIV 10 0% 100 90 mA 35 S X V R ≥ For a 5 V single-supply operation, RX should have a minimum value of 143 Ω. Figure 33. Scope Photo of the VCOM Instantaneous Peak Current |
类似零件编号 - AD8565AKSZ-REEL7 |
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类似说明 - AD8565AKSZ-REEL7 |
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